What is the mass of a piece of iron if it absorbs 5575 joules of heat and its specific heat capacity is 0.95 J/g°C? The initial temperature of the iron is 20.0°C and is raised to 30°C.

Only include numbers and the decimal point in your answer. If necessary, round to the hundredths (two spots to the right of the decimal point) place. For example "34.22."

The mass of iron piece = 586.84

Explanation:

Given,

Heat absorbed by iron piece(Q) = 5575 Joules.

specific heat capacity(Cp) = 0.95 J/g°C.

initial temperature(T₁) = 20.0°C

Final temperature(T₂) = 30.0°C

Mass of iron piece(m) = ?

The mass of iron piece can be calculated by using the formula ,

Q = (mass) (ΔT) (Cp)

Here, ΔT = T₂ - T₁ = 30°C - 20°C = 10°C

Substituting values we get,

5575 = (m)(10)(0.95)

Solving, we get,

m = 586.84 grams.

Therefore, mass of iron piece = 586.84 grams.