Convert 6mol NO2 into grams Convert 800 grams of LiO into moles! Convert 4500 grams of SO2 into molecules! Convert 30 mol H2O into grams! Convert 8mol CO into grams!

1. 276 g of NO₂

2. 34.8 moles of LiO

3. 4.23×10²⁵ molecules of SO₂

4. 540 g of H₂O

5. 224 g CO

Explanation:

Let's define the molar mass of the compound to define the moles or the grans of each.

Molar mass . moles = Mass

Mass (g) / Molar mass = Moles

1. 6 mol . 46 g / 1 mol = 276 g of NO₂

2. 800 g . 1mol / 22.94 g = 34.8 moles of LiO

3. To determine the number of molecules, we convert the mass to moles and then, we use the NA (1 mol contains 6.02×10²³ molecules)

4500 g . 1mol / 64.06 g = 70.2 moles of SO₂

70.2 mol . 6.02×10²³ molecules / 1 mol = 4.23×10²⁵ molecules of SO₂

4. 30 mol . 18g / 1 mol = 540 g of H₂O

5. 8 mol . 28g /  1mol = 224 g CO

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

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