A sample of gas at 25 degrees celsius and 101.3 kPa occupies 0.30 liters. What is the new volume of the gas if the pressure is increased to 180 kPa and the temperature is lowered to 0 degrees celsius

The new volume is 0.155 L

Explanation:

Step 1: Data given

Temperature  = 25.0 °C = 298 K

Pressure = 101.3 kPa = 0.99975327 atm

Volume = 0.30 L

The pressure increases to 180 kPa = 1.77646 atm

The temperature lowers to 0°C = 273 K

Step 2: Calculate new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 0.99975327 atm

⇒with V1 = the initial volume = 0.30 L

⇒with T1 = the initial temperature = 298 K

⇒with P2 = the new pressure = 1.77646 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the new temperature = 273 K

(0.99975327 * 0.30)/298 = (1.77646 * V2)/273

V2 =0.155 L

The new volume is 0.155 L

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