Atom A's electrons tend to move farther away from the nucleus, and Atom B's electron tends to stay closer to the nucleus. Which atom do you think would have a higher electronegativity if Atom A and Atom B bonded together?

when they form a bond, Atom B has higher electronegativity than atom A.

Explanation:

Electronegativity is the tendency of an atom in a bond pair to attract the shared pair of electron towards itself.

Covalent bond is the bond which is formed with the sharing of the electrons between the two atoms which are taking part in the bond. It is generally formed between the atoms with similar electronegativity values.

It is the bond which is generally occurs within non metals as they share electrons to complete their octet.

The difference in the electronegativity values of the atoms involving in a covalent bond must not exceed the value of 1.7 .

The electrons in case of atom B are close to the nucleus and in case of atom N are far from the nucleus. Thus, when they form a bond, Atom B has higher electronegativity than atom A.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

the answer is true. hope it .