What volume 4.5 mol/dm3 nitric acid should be diluted with water to form 2.5 dm3 of 1.20 mol/dm3 nitric acid.

0.67 dm³

Explanation:

We are given;

Initial molarity, M1 as 4.5 mol/dm³Final volume, V2 as 2.5 dm³Final Molarity , M2 as 1.20 mol/dm³

We are required to determine the initial volume, V1

To answer the question we need to know the dilution formula;

The dilution formula is given by;

M1V1 = M2V2

Thus;

V1 = M2V2 ÷ M1

    = ( 1.20 mol/dm³ × 2.5 dm³) ÷ 4.5 mol/dm³

    = 0.67 dm³

Hence, the initial volume before dilution is 0.67 dm³

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)

Inot sure what it is i sorry : ((