Balance the chemical equation given below, and calculate the volume of nitrogen monoxide gas produced when 8.00 g of ammonia is reacted with 12.0 g of oxygen at 25°C? The density of nitrogen monoxide at 25°C is 1.23 g/L. ___ NH3(g) + ___ O2(g) → ___ NO(g) + ___ H2O(l)

→

Volume of NO = 11.46 lit

Explanation:

From the above written equation we can easily understood that here acts as an limiting reagent.

4 mol of can produce 4 mol of

Molecular weight of = 17 g/mol

So, 8 g of means = = 0.470 mol

So, 0.470 mol of will produce 0.470 mol of NO

Molecular weight of NO = 30 g/mol

So, 0470 mol of NO means (30 × 0.470 ) = 14.1 g

we know that, Density =

 Volume of NO = = 11.46 lit