Be sure to answer all parts. Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow] (3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4 [fast] (4) C6H5SO3− + H3O+ → C6H5SO3H + H2O [fast] (a) Write the overall equation for this reaction. (b) Write the overall rate law for the initial rate of the reaction. Rate =

C6H6 + H2SO4 ---> C6H5SO3H + H2O

k [H2SO4]^2 [C6H6]

Explanation:

In writing the rate equation for a reaction, all the steps in the reaction sequence are summed and transient intermediates are taken into consideration.

Writing rate equation began at the slowest step as shown in the image attached to this answer below. This is because the slowest step determines the rate of reaction. Concentration of intermediates are usually expressed in terms of concentration of reactants as intermediates do not enter the rate equation.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.