A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.350 atm . Part A What is the partial pressure of argon, PAr, in the flask?

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13

From ideal gas equation P V = m RT

⇒ P =

Put all the values in above formula we get

⇒ P = × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

it is a solid

explanation: