Use Hess's Law or the summation equation to calculate the ΔHrxn. Round to the nearest tenth!!

___NF(g) + ___F2 (g) --> ___NF2 (g)

½N2 (g) + ½F2 (g) -> NF (g) Hf = 86.6 kJ

½N2 (g) + F2 (g) -> NF2 (g) Hf = 33.8 kJ

The ΔHrxn with the nearest tenth will have value of -60 K.

Explanation:

NF(g) + ___F2 (g) --> ___NF2 (g

data given:

½N2 (g) + ½F2 (g) -> NF (g) Hf = 86.6 kJ

½N2 (g) + F2 (g) -> NF2 (g) Hf = 33.8 kJ

Hess's law of heat is summation says that total change in enthalpy during a reaction is same whether the reaction is direct or in various steps.

½N2 (g) + ½F2 (g) -> NF (g) Hf = 86.6 kJ

reversing the equation we get:

NF  -> ½N2 (g) + ½F2 (g)

Heat of enthalpy becomes negative so -86.6 KJ

Now adding both the reactions:

NF  -> ½N2 (g) + ½F2 (g)

½N2 (g) + F2 (g) -> NF2 (g) Hf = 33.8 kJ

Removing the common entities from the reaction we get

F2 (g) + NF (g) --> ½F2 (g) +  NF2 (g) Hf

the summation of enthalpy is

-86.6+ 33.8

= 52.8 KJ

The nearest tenth will be -60 KJ.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.