Provided that the molar mass of a compound is 543.52 g/mol, how many mg do you need to add to 17 mL of solvent to yield a solution molarity of 3 M?

N. B. M = (mol/L)
Select one:
a. 10.66
b. 27719520.00
c. 27.72
d. 27719.52
e. 3079946.67

27719.52 mg

Explanation:

From the question, we have;

Required to determine the mass of the compound needed to make the solution.

We know that;

Molarity = Moles ÷ Volume

Therefore;

Moles = Molarity × Volume

Hence;

Moles of the compound = 3 M × 0.017 L

                                         = 0.051 Moles

But;

Mass = Moles × Molar mass

        = 0.051 moles × 543.52 g/mol

        = 27.71952 g

But, 1 g = 1000 mg

Therefore;

Mass (in mg) = 27719.52 mg

answer: mole of the gas

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