Calculate the bond energy of HBr. Bond energy of H2 is 436KJ/mol and that of Br2 is 193KJ/mol.

ΔH3 =  1/2 (629) - ΔH^0

Explanation:

Given data:

Bond energy of H2 = ΔH1 =  436 Kj/mol

Bond energy of Br2 = ΔH2 = 193 Kj/mol

To find:

Let bond energy of HBr = ΔH3 = ?

Equation:

H2 + Br2 → 2HBr

enthalpy of formation of HBr = ΔH1 + ΔH3 - 2(ΔH3)

ΔH^0 = 436 + 193 -   2(ΔH3)

(436 + 193) - ΔH^0 = 2(ΔH3)

ΔH3 =  1/2 (629) - ΔH^0

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

the answer is na (sodium)