5.8 L of gas at 760 mm Hg is expanded at constant temperature until the pressure is 430 mm Hg. what is the volume of the gas?

10.3L

Explanation:

The following were obtained from the question:

V1 = 5.8 L

P1 = 760mmHg

P2 = 430mmHg

V2=?

The new volume can be obtain as follows:

P1V1 = P2V2

5.8 x 760 = 430 x V2

Divide both side by 430

V2 = (5.8 x 760) /430

V2 = 10.3L

Therefore, the new volume is 10.3L

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol