Suppose that 40 mL of water is poured simultaneously into three containers, each having a different sediment. After 10 seconds, 5 mL remains atop Sediment A, 20 mL of water remains atop Sediment B, and 28 mL of water remains atop Sediment C. Water continues to seep into each of the substances. Which substance has the lowest permeability?

The answer to your question is Sediment C

Explanation:

Permeability is the property of passing through a material without physically or chemically affecting it.

If a substance is very permeable, it will pass through a material rapidly others substances can be permeable but can not pass through the material quickly.

In the data given, we can conclude that the third substance is the least permeable because less quantity of water has passed through it.

where is the following

explanation:

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !