Consider the chemical formula for one unit of aluminum sulfate, Al2(SO4)3. How many total atoms would be present in 22 units of aluminum sulfate?

1.32×10²⁵ atoms of sulfate are contained in 22 units of it

Explanation:

1 unit = 1 mol

Al₂(SO₄)₃ → Aluminum sulfate

As 1 unit = 1 mol, 1 unit has 6.02×10²³ atoms of aluminum sulfate.

Let's make a rule of three:

1 unit of Al₂(SO₄)₃ contains 02×10²³ atoms

Then, 22 units of Al₂(SO₄)₃ must contain (22 . 6.02×10²³) / 1 = 1.32×10²⁵ atoms

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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