Chemistry, 13.03.2020 18:34 chloeann5397

Aspirin is prepared by reaction of salicylic acid (C7H6O3) with acetic anhydride (C4H6O3)according to the following equation:
C7H6O3Salicylicacid+C4H6O3Aceticanh ydride→C9H8O4Aspirin+CH3COOHAcetica cid

a. How many grams of acetic anhydride are needed to react with 3.07 g of salicylic acid?
b. How many grams of aspirin will result?
c. How many grams of acetic acid are formed as a by-product?

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Answer from: cookiebrain72

For a: The mass of acetic anhydride reacts is 2.25 grams

For b: The mass of aspirin produced is 3.96 grams

For c: The mass of acetic acid produced is 1.32 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of salicylic acid = 3.07 g

Molar mass of salicylic acid = 138.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of salicylic acid}=\frac{3.07g}{138.12g/mol}=0.022mol$

The chemical equation for the reaction of salicylic acid and acetic anhydride follows:

$C_7H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+CH_3COOH$

For a:

By Stoichiometry of the reaction:

1 mole of salicylic acid reacts with 1 mole of acetic anhydride

So, 0.022 moles of salicylic acid will react with = $\frac{1}{1}\times 0.022=0.022mol$ of acetic anhydride

Now, calculating the mass of acetic anhydride from equation 1, we get:

Molar mass of acetic anhydride = 102.1 g/mol

Moles of acetic anhydride = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of acetic anhydride}}{102.1g/mol}\\\\\text{Mass of acetic anhydride}=(0.022mol\times 102.1g/mol)=2.25g$

Hence, the mass of acetic anhydride reacts is 2.25 grams

For b:

By Stoichiometry of the reaction:

1 mole of salicylic acid produces 1 mole of aspirin

So, 0.022 moles of salicylic acid will produce = $\frac{1}{1}\times 0.022=0.022mol$ of aspirin

Now, calculating the mass of aspirin from equation 1, we get:

Molar mass of aspirin = 180.16 g/mol

Moles of aspirin = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of aspirin}}{180.16g/mol}\\\\\text{Mass of aspirin}=(0.022mol\times 180.16g/mol)=3.96g$

Hence, the mass of aspirin produced is 3.96 grams

For c:

By Stoichiometry of the reaction:

1 mole of salicylic acid produces 1 mole of acetic acid

So, 0.022 moles of salicylic acid will produce = $\frac{1}{1}\times 0.022=0.022mol$ of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.022 moles

Putting values in equation 1, we get:

$0.022mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.022mol\times 60g/mol)=1.32g$

Hence, the mass of acetic acid produced is 1.32 grams

Answer from: Quest

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Answer from: Quest

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Aspirin is prepared by reaction of salicylic acid (C7H6O3) with acetic anhydride (C4H6O3)according t...