The pH of an acetic acid solution is 4.0. (10n= 1en).

calculate the [H+] moles/liters what is the [OH-? moles/liters

1. [H+] = 1 x 10^-4mol/L

2. [OH-] = 1 x 10^-10mol/L

Explanation:

1. From the question given, the pH is 4.0. We can obtain the value of the value of the hydrogen ion concentration [H+] as follows:

pH = —Log[H+]

4 = —Log[H+]

—4 = Log[H+]

Anti-log of —4

[H+] = 1 x 10^-4mol/L

2. Recall: [H+] x [OH-] = 1 x 10^-14

But [H+] = 1 x 10^-4mol/L

1 x 10^-4 x [OH-] = 1 x 10^-14

Divide both side by 1 x 10^-4mol/L

[OH-] = 1 x 10^-14/1 x 10^-4

[OH-] = 1 x 10^-10mol/L

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2