Consider the following scenario: 4.000 g of solid, reagent grade NaOH was dissolved in enough water to make 1.00 L of solution. What is the calculated molarity of the solution? The formula weight of NaOH is 40.0 g/mol. a. 0.100 M b. 10.0 M c. 1.00 x 10-2 M d. 1.00 M How will the actual molarity of the NaOH solution from the previous question compare to the calculated molarity?
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