HELP PLEASE
I have a solution that contains too much solute per liter of solvent, so I will need to dilute the solution by adding more solvent. In this case the solvent is water. If my initial concentration is 12 M and my starting volume is 3.0 L, what will be the new volume if I dilute my concentration to 3.25 M?

The answer to your question is 11.0 L

Explanation:

Data

[Concentration 1] = 12 M

Volume 1 = 3.0 L

[Concentration 2] = 3.25 M

Volume 2 = ?

Process

1.- To solve this problem, use the dilution formula

        Concentration 1 x Volume 1 = Concentration 2 x Volume 2

- Solve for Volume 2

        Volume 2 = Concentration 1 x Volume 1 / Concentration 2

- Substitution

        Volume 2 = 12 x 3 / 3.25

- Simplification

        Volume 2 = 36 / 3.25

- Result

        Volume 2 = 11 L