A sample of gas occupies a volume of 71.1 mL . As it expands, it does 123.3 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas

The final volume of the gas is 1250 mL

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

W = amount of work done  for expansion process = -123.3 J = -1.217 L.atm   (Conversion factor:  1 L.atm = 101.33 J)

Work done for expansion process is taken as negative

P = pressure  = 783 torr = 1.03 atm     (Conversion factor:  1 atm = 760 torr)

= initial volume  = 71.1 mL = 0.0711 L   (Conversion factor:  1 L = 1000 mL)

= final volume = ?

Putting values in above equation, we get:

Hence, the final volume of the gas is 1250 mL

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considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.