Chemistry, 12.03.2020 06:02 tiwaribianca475

Which one of the following equations is the net ionic equation for the reaction of aqueous sodium hydroxide (NaOH) with aqueous hydrochloric acid (HCl)? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) H+(aq) + Cl‒(aq) + Na+(aq) + OH‒(aq) → Na+(aq) + Cl‒(aq) + H2O(l) H+(aq) + Cl‒(aq) + Na+(aq) + OH‒(aq) → NaCl(aq) + H2O(l) H+(aq) + OH‒(aq) → H2O(l)

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Answer from: darrieg

H+(aq) + OH-(aq) → H2O(l)

Explanation:

Step 1: Data given

aqueous sodium hydroxide = NaOH(aq)

aqueous hydrochloric acid =HCl(aq)

Step 2: The (un)balanced equation

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

For 1 mol HCl we need 1 mol NaOH to produce 1 mol NaCl and 1 mol H2O

This equation is already balanced.

Step 3: The net ionic equation

H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + Cl-(aq) + H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

H+(aq) + OH-(aq) → H2O(l) (The last option is correct)

Answer from: Quest

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is 2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that 10 dm = 1 m ⇔ 10³ dm³ = 1 m³then we use the fact that 10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting: $\dfrac{\text{2 mol}}{\text{dm}^{3}} \cdot \dfrac{\text{10}^3\text{ dm}^3}{\text{1 m}^3} \cdot \dfrac{\text{1 m}^3}{10^6\text{ cm}^3} \\ \\ = \dfrac{\text{2 mol}}{1} \cdot \dfrac{\text{10}^3}{1} \cdot \dfrac{1}{10^6\text{ cm}^3} \qquad \text{\footnotesize cancelling units} \\ \\ = \dfrac{2\text{ mol}}{10^3 \text{ cm}^3} \\ \\ = 0.002\text{ mol/cm}^3$ now we have to find the moles of hydrochloric acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by molar mass = (mass ca) + (mass c) + 3(mass o) = 40 + 12 + 3(16) = 100 g/molconvert the given 5 g to moles: mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃) = 0.05 mol hcl * 2 = 0.1 mol hcl we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get volume = moles / concentration volume = 0.1 mol / (0.002 mol/cm³) volume = 50 cm³

Answer from: Quest

Heat of fusion= heat/mass heat of fusion = 12.03kj/36 g= 0.3342 kj/g or 334.2 j/g

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Which one of the following equations is the net ionic equation for the reaction of aqueous sodium hy...