What is the final volume of a 400 ML sample that is subjected To a temperature change from 22 Celsius to 30 Celsius in a pressure change from 760 am MHG to 360 MMHG

The answer to your question is  V2 = 867.3 mL

Explanation:

Data

Volume 1 = V1 = 400 ml

Temperature 1 = T1 = 22°C

Pressure 1 = P1 = 760 mmHg

Volume 2 = V2 = ?

Temperature 2 = T2 = 30°C

Pressure 2 = P2 = 360 mmHg

Process

1.- Convert Celsius to Kelvin

T1 = 22 + 273 = 295°K

T2 = 30 + 273 = 303°K

2.- Use the Combined gas law

              P1V1/T1 = P2V2/T2

- Solve for V2

            V2 = P1V1T2 / T1P2

- Substitution

            V2 = (760 x 400 x 303) / (295 x 360)

- Simplification

            V2 = 92112000 / 106200

-Result

            V2 = 867.3 mL

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml