What is the percent yield of lithium chloride if a reaction starts with 20.0 g lithium hydroxide and yields 6.00 g lithium chloride? LiOH+KCl⟶LiCl+KOH

The percent yield of lithium chloride if a reaction starts with 20.0 g lithium hydroxide and yields 6.00 g lithium chloride is 17.2 %

Explanation:

The balanced chemical reaction is

To calculate the moles, we use the equation:

a) moles of

b) moles of

According to stoichiometry :

1 mole of produces =  1 mole of

Thus 0.83 moles of produce= of

Mass of

The theoretical yield of = 34.9 g

The experimental yield of ethanol = 6.00  g

Now we have to calculate the percent yield of ethanol.

Therefore, the percent yield is, 17.2 %

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

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