Particles with a charge of +5e are incident on a target. If the beam of particles carries a current of 138 µA, how many particles strike the target in a period of 25.0 s? particles

Explanation:

Current (I) is the flow of charge (Q) per unit of time (t). The ampere unit is defined as the amount of charge that flows in one second.

You have the current, 138 µA, and the time, 25.0s, thus you can calculate the charge:

Now calculate the number of particles with a charge of +5eV that have a charge of 0.00345C

The charge of one electron is

Then, a positve charge equivalent to the magnitude of the charge of 5 electrons (one particle) is:

Divide the total charge by the charge of a particle:

Rounding to 3 significant figures that is    

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.