How many grams of lithium nitride needs to react with excess water at stp to produce 15.0 l of ammonia

Mass = 24.4 g

Explanation:

Given data:

Mass of lithium nitride needed = ?

Volume of ammonia = 15.0 L

Solution:

Chemical equation:

Li₃N + 3H₂O   → NH₃ + 3LiOH

One mole = 22.414 L

We will compare the volume of lithium  nitride and ammonia.

                                NH₃             :            Li₃N

                              22.414           :              22.414

                               15.0              :               15.0  

Number of moles of lithium nitride:

PV = nRT

n = 1 atm ×15 L / 0.0821 atm.L / mol.K × 273 K

n = 15 /22.41 /mol

n =0.7

Mass of Lithium nitride:

Mass = number of moles × molar mass

Mass = 0.7 mol × 34.83 g/mol

Mass = 24.4 g

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.