What is the mass of 8.83 × 10 ^23 formula units of iron (III) oxide, Fe2O3?

234.68g

Explanation:

We understood from Avogadro's hypothesis that 1mole of any substance contains 6.02x10^23 atoms. Therefore, 1mole of Fe2O3 also contains 6.02x10^23 atoms

1 mole of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g

Now, if 160g of Fe2O3 contains 6.02x10^23 atoms,

Therefore Xg of Fe2O3 will contain 8.83×10^23 atoms i.e

Xg of Fe2O3 = (160x8.83×10^23)/6.02x10^23 = 234.68g

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

the answer is definitely c.