Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =

The question is incomplete , complete question is :

Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =31.5

Given: [TZ] = 0.5461 mol/L

The concentration of TZ solution in μmol/L is 546 μmol/L

Explanation:

Molarity of the TZ solution = 0.5461 mol/L

This means that 0.5461 moles of TZ are present in 1 L of solution.

Moles of TZ = 0.5461 mol

So, the concentration of TZ solution in μmol/L is :

546.1 μmol/L ≈ 546 μmol/L

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

answer carbon and three oxygen atoms;