Chemistry, 10.03.2020 19:06 eta20

Select the correct answer. What effect will the number of particles and temperature have on the rate of diffusion of gas molecules? A. The rate of diffusion decreases with the increase in number of particles and temperature. B. The rate of diffusion increases with the increase in number of particles and temperature. C. The rate of diffusion increases with the increase in number of particles and decrease in temperature. D. The rate of diffusion decreases if the number of particles and temperature are kept constant. E. The rate of diffusion increases if the number of particles and temperature are kept constant. Reset Next

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Answer from: ariannapenny98

The rate of diffusion increases with the increase in number of particles and temperature.

Explanation:

Diffusion occurs due to the collision of the particles in the gas phase and causes them to disperse from a region of high concentration to that of low concentration until the particles are distributed evenly in the space – which is what is called equilibrium.

The more the particles, therefore, the higher the rate of collisions between the particles hence a higher rate of diffusion. Also, higher temperatures mean the particles have higher kinetic energy. The collisions rates are higher and with higher kinetic energy therefore increasing the rate of diffusion.

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

Answer from: Quest

08.01 hope this and can i get brainlist? ?

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