Jacqueline isolated an interesting new protein from the broth of a yeast culture. After purification of the protein, she requested an amino acid analysis and found that the protein contained 0.48 % tryptophan by weight (tryptophan Mr=204).

a. Calculate the minimum molecular weight of the protein (i. e., assuming there is only one tryptophan residue per protein molecule).
b. Size-exclusion chromatography of the protein gave a molecular weight estimate of 53500. How many tryptophan residues are present in a molecule of the new protein?

a)minimum molecular weight of the protein= 42500g

b) new protein contains 262.25 molecules of tryptophan

Explanation:

a) if 0.48 % by weight of tryptophan has the molecular weight=204g

It implies that the molecular weight of the 100% protein will be 100×204/0.48=42500g of protein as the minimum molecular weight of the protein

b) new protein Molecular weight= 53500

1-molecule of tryptophan has Mm = 204,

Hence 53500/204= 262.25 molecules of tryptophan in the new protein

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hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.