A) The 1H-NMR spectrum of 1-bromopropane shows three signals and the 1H-NMR spectrum of 2-bromopropane shows two signals. Draw these two molecules and determine the relative integrals of each signal. B) Compound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.
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Chemistry, 22.06.2019 01:30, jusicca1109
100 points answer quick the table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 10 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of the two atoms? both are unreactive. both are highly reactive. a is unreactive and d is reactive. a is reactive and d is unreactive.
Answers: 1
Chemistry, 22.06.2019 09:00, bibhu42kumarp7o4ss
At 300 mm hg, a gas has a volume of 380 l, what is the volume at standard pressure
Answers: 1
A) The 1H-NMR spectrum of 1-bromopropane shows three signals and the 1H-NMR spectrum of 2-bromopropa...