If the pHpH of a 1.00-inin. rainfall over 1400 miles2miles2 is 3.60, how many kilograms of sulfuric acid, H2SO4H2SO4, are present, assuming that it is the only acid contributing to the pHpH? For sulfuric acid, Ka1Ka1K_a1 is very large and Ka2Ka2K_a2 is 0.012.

mass H₂SO₄ = 1.45 x 10⁶ kg H₂SO₄

Explanation:

At pH 3.70, H2SO4 can be regarded as being fully dissociated. The dissociation reaction is

H₂SO₄(l) ⇄ 2H⁺(aq) + SO₄²⁻(aq)

Since pH = -log₁₀[H⁺]

[H⁺] = 2.5 x 10⁻⁴ M

Since there are 2 moles of H⁺ for every mole of H₂SO₄

[H₂SO₄] = 0.5 * [H⁺]

=0.5 * 2.5 x 10⁻⁴ M

[H₂SO₄] = 1.25 x 10⁻⁴ M

Convert the amount of rain and the area into SI units

Rain = 1.00 in * 0.0254 m/in

Rain = 0.0254 m

Area = 1600 miles² * 2589988.11 m²/miles²    = 4.661 x 10⁹  m²

Calculate the volume of water

Volume = Rain * Area

=0.0254 m * 4.661 x 10⁹

Volume = 1.184 x 10⁸ m³

Calculate the number of kilo moles of H₂SO₄

kilo moles H₂SO₄ = [H₂SO₄] * Volume

=1.25 x 10⁻⁴ M * 1.184 x 10⁸ m³

kilo moles H₂SO₄ = 14,800 k mole

Calculate the mass of H₂SO₄

mass H₂SO₄ = kilo moles H₂SO₄ * MW H₂SO₄

= 14800 k mol * 98.07848 kg/kmol

mass H₂SO₄ = 1.45 x 10⁶ kg H₂SO₄

possibly, yes.

explanation:

the amount of sugar you take in is dangerously high, risk of heart disease, high risk of diabetes, and etc.

elements make up everything, and they combine to make compounds.

the answer is c