A student is given an antacid tablet that weighs 5.6863 g. The tablet was crushed and 4.3705 g of the antacid was added to 200 mL of simulated stomach acid. This was allowed to react and then filtered. It was found that 25.00 mL of this partially neutralized stomach acid required 11.49 mL of a NaOH solution to titrate it to a methyl red end point. It took 27.5 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid. What percent (%) of the original amount of stomach acid in the 25.00-mL sample was neutralized during the titration

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.