The following three σ-ϵ data points are provided for a titanium allow for aerospace applications: ϵ = 0.002525 (at σ = 300 MPa), ϵ = 0.005051 (at σ = 600 MPa), and ϵ = 0.008029 (at σ = 900 MPa). Calculate E for this alloy.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the temperature of the gas, in k, not celsius.

i think its 100

i hope this !

4d^55s^1 ( third choice)