Problem Page Question An analytical chemist weighs out of an unknown monoprotic acid into a volumetric flask and dilutes to the mark with distilled water. He then titrated this solution with solution. When the titration reaches the equivalence point, the chemist finds he has added of solution. Calculate the molar mass of the unknown acid. Round your answer to significant digits.

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An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.1600M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 6.5mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits.

The molar mass of the unknown acid is 89 g/mol

Explanation:

To calculate the molarity of solution, we use the equation:

Molarity of NaOH solution = 0.1600 M

Volume of  NaOH solution = 6.5 mL

Putting values in above equation, we get:

The chemical equation for the reaction of monoprotic acid and NaOH follows:

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HA

So,  moles of NaOH will react with = moles of HA

To calculate the molar mass for given number of moles, we use the equation:

Given mass of HA = 0.093  g

Moles of monoprotic acid =

Putting values in above equation, we get:

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explanation:

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.