Calculate the concentration of all ions present in 5.96 g Na2S in 1.00 L of solution.

[Na+] = 0.1528 M

[S^2-] = 0.0764 M

Explanation:

Step 1: Data given

MAss of Na2S = 5.96 grams

Volume of solution = 1.00 L

Molar mass Na2S = 78.045 g/mol

Step 2: Calculate moles Na2S

Moles Na2S = Mass Na2S / molar mass Na2S

Moles Na2S = 5.96 grams / 78.045 g/mol

Moles Na2S = 0.0764 moles

Step 3: Calculate moles ions

For 1 mol Na2S we have 2 moles Na+ and 1 mol S^2-

For 0.0764 moles Na2S we have 0.0764 moles S^2- and 2*0.0764 = 0.1528 moles Na+

Step 4: Calculate concentration of ions

[Na+] = 0.1528 moles / 1 L = 0.1528 M

[S^2-] = 0.0764 moles / 1L = 0.0764 M

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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