Chemistry, 07.03.2020 19:53 genyjoannerubiera

What are the factor that affect the survival of the electron in the same orbit in the ground state of an atom?

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Answer from: mariahcrook7

The energy of an electron in a single electron atom is determined through the principal of quantum number.

The order in which the energy of the various orbitals increases is 1s < 2s = 2p < 3s = 3p = 3d <4s = 4p = 4d= 4

Explanation:

The factor that affect the survival of the electron in the same orbit in the ground state of an atom are:

For a given value of the principal quantum number, the s orbital electron will be more tightly bound to the nucleus than p orbital electron, which is more tightly bound in comparison to a d orbital electron. s orbital electrons will have a lesser amount of energy (more negative) than that of p orbital electrons which will have lesser energy than that of d orbital electrons. The energy of orbitals depends upon the values of both principal quantum number (n) and azimuthal quantum number (l). Hence, the lower the value of (n + l) for an orbital, the lower is its energy. For the cases where we have two orbitals having the same value of (n + l), the orbital with a lower value of n (principal quantum number) will have the lower energy.The energy of the orbitals in the same subshell decreases with increase in the atomic number (Zeff).

Answer from: Quest

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer

Answer from: Quest

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o