What is the density of oxygen gas (O2) at 2.3 atmospheres and 305 Kelvin? Show all of the work used to solve this problem.

2.94g/L

Explanation:

First, let us derive an expression for the density, using the ideal gas equation:

PV = nRT (1)

V = nRT/ P (2)

Recall:

Number of mole(n) = mass(m)/Molar Mass (M)

n = m/M

Substituting the value of n into equation 2:

V = nRT/ P

V = mRT/ MP

Now Divide both side by m

V/m = RT/ MP

Inverting the above equation, we have:

m/V = MP/RT

But Density = m/V

Density = MP/RT

From the question given, we obtained the following data:

P = 2.3atm

T = 305K

Molar Mass of O2 = 16x2 = 32g/mol

R = 0.082atm.L/K /mol

Density = (32x2.3)/(0.082x305)

Density = 2.94g/L

the answer is 0.8m.

by: nicholas

i think its 5049.

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