If Co(NH3)63+ has a λmax at 440 nm, calculate ΔE for the complex. A) 2.72 x 10-4 kJ/mol B) 4.52 x 10-2 kJ/mol C) 2.72 x 10 2 kJ/mol D) 2.72 x 10 5 kJ/mol E) 2.72 x 10 9 kJ/mol Group of answer choices

The energy of the complex is

Explanation:

To calculate the energy of the complex, we use the equation given by Planck which is:

where,

= Wavelength of the complex =    (Conversion factor:   )

h = Planck's constant =

c = speed of light =

= Avogadro's number =

= energy of the complex

Putting values in above equation, we get:

Conversion factor used:  1 kJ = 1000 J

Hence, the energy of the complex is

The complex energy is option(C) .

Explanation:

To calculate the energy of the complex, by using Planck's equation.

Where,

h = Planck's constant = .

c = speed of light = .

= Avogadro's number = .

E = energy of the complex.

Substitute all the required values in the equation:

.

The energy of the complex is .

Learn more about energy of the complex, refer:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.