Identify the atoms that correspond to each of the following electron configurations. Then, write the Lewis symbol for the common ion formed from each atom: (a) 1s22s22p5 (b) 1s22s22p63s2 (c) 1s22s22p63s23p64s23d10 (d) 1s22s22p63s23p64s23d104p4 (e) 1s22s22p63s23p64s23d104p1

a. 1s² 2s² 2p5 → Fluorine

b. 1s² 2s² 2p6 3s² → Magnesium

c. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 → Zinc

d. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 4p4 → Selenium

e. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 4p1 → Gallium

Explanation:

The electronic configuration of element are represented base on their atomic number. The shells are s p d and f. The s shell can only accommodate 2 electrons , p shell can only accommodate 6 electrons , d can accommodate maximum of 10 electrons and f can accommodate maximum of 14 electrons.  

The following configuration are

a. 1s² 2s² 2p5 → it has 9 electrons and 9 protons. The atomic number is 9 , therefore the element is Fluorine.

b. 1s² 2s² 2p6 3s² → Atomic number is 12 . The element is Magnesium.

c. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 → Atomic number is 30. The element is Zinc.

d. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 4p4 → Atomic number is 34 . The element is Selenium.  

e. 1s² 2s² 2p6 3s² 3p6 4s² 3d10 4p1 → Atomic number is 31. The element is Gallium.

The lewis structure of each element is represented with dots around the symbol of the element. The number of dots is the number of valency electron.

The lewis structure is represented in picture below

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