Part A How many moles of NH3 can be produced from 13.5 mol of H2 and excess N2? Express your answer numerically in moles. View Available Hint(s) nothing mol NH3

9moles of NH3

Explanation:

First, we need to write a balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the equation,

3 moles of H2 produced 2moles of NH3.

Therefore, 13.5 mol of H2 will produce = (13.5 x 2)/3 = 9moles of NH3