Estimate the following: a) The volume occupied by 18 kg of ethylene at 55°C and 35 bar. b) The mass of ethylene contained in a 0.25-m3 cylinder at 50°C and 115 bar.

Explanation:

(a)   The given data is as follows.

             T = = (55 + 273) K

                = 328 K

             P = 35 bar = 3500 kPa

Let us assume that moles of ethylene present are 1 kmol and according to the ideal gas equation, PV = nRT.

Or,            V =

                    =

                   = 0.779

Hence, the volume occupied by 18 kg of ethylene at and 35 bar is 0.779 .

(b)   The given data is as follows.

              V = 0.25

               T = = (50 + 273) K

                  = 323 K

                P = 115 bar = 11500 kPa

Using ideal gas equation first, we will calculate its moles as follows.

            n =

               =

               = 1.07 mol

Since,  moles =

Hence, mass of ethylene will be calculated as follows.

                moles =

             1.07 mol =

                   mass = 29.96 g

Therefore, mass of given ethylene is 29.96 g.

answer; i believe that the correct answer is (a) potassium(k)

d : a person who learns about the world by observing it. no that is not a smiley face

explanation: