What is the volume of 2 mol of chlorine gas at stp? 2.0 l 11.2 l 22.4 l 44.8 l

We know that the ideal gas equation is

PV = nRT

Where

P = Pressure of gas

V = volume of gas

R = ideal gas equation constant = 0.0821 L atm / mol K

n = moles

Given that

STP : standard temperature and pressure

standard pressure = 1 atm

Standard temperature = 273.15 K

volume = ?

n = 2 mole

Volume = nRT / P

volume = 2 X 0.0821 X 273.15 / 1 =44.8 Litres or 44.8 dm^3

We also know that the volume occupied by one mole of a gas at STP is 22.4L so the volume occupied by two moles of gas will be 2 X 22.4 = 44.8 L

Hence chlorine will occupy 44.8 L if its two moles were taken

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.