The volume of a sample of chlorine gas is 8.00 liters at 45.0 degrees Celsius and 0.966 atm. How many moles of chlorine are present in the sample? R = 0.0821 (atm)(L)(mol-1)(K-1)

Number of moles of Cl₂ = 0.3 mol

Explanation:

Given data:

Number of moles of Cl₂ = ?

Pressure = 0.966 atm

Volume = 8.00 L

Temperature = 45°C

Solution:

The given problem will be solve by using general gas equation, which is,

PV = nRT

R = general gas constant (0.0821 atm.L/mol.K)

Now we will convert the °C into K.

Temperature = 45+ 273 = 318 K

Now we will put the values in formula.

n = PV/RT

n = 0.966 atm × 8.00 L / 318 K ×0.0821 atm.L/mol.K

n = 7.728/26.1078 /mol

n = 0.3 mol

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