If there are 160 Calories in 28 g in 1 serving of Flamin' Hot Cheetos, how many gram(s) of Cheetos must you burn to raise the temperature of 20.0 mL of water 1oC?

3.5 g

Explanation:

The density of water is 1 g/mL. The mass (m) corresponding to 20.0 mL is 20.0 g.

We can calculate the heat (Q) required to raise the temperature of 20.0 mL of water 1 °C (ΔT).

Q = c × m × ΔT = 1 cal/g.°C × 20.0 g × 1 °C = 20 cal

where,

c is the specific heat capacity of water

There are 160 calories in 28 g of Cheetos. The mass that releases 20 cal is:

20 cal × (28 g/160 cal) = 3.5 g

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.