An empirical formula: 1. gives the relative number of ions of each element per formula unit. 2. gives the number of ions of each element per formula unit. 3. uses lines to represent covalent bonds and shows how atoms in a molecule connect or bond to each other. 4. gives the relative number of atoms of each element per formula unit.5. gives the actual number of atoms of each element per formula unit.

4.  gives the relative number of atoms of each element per formula unit

Explanation:

An empirical formula -

It refers to the formula which determined the simplest whole - number ratio of all the atoms in a given species , is referred to as an empirical formula .

In simple terms ,

It is he smallest formula of the whole number which when multiplied by some whole number gives the actual structure of the compound .

Hence , from the given information of the question ,

The correct option for empirical formula is 4.

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.