For the reaction of A and B forming C, A(g)+ B(s)⇌ 2C(g) how will the reaction respond to each of the following changes at equilibrium? Drag the appropriate items to their respective bins.
a) double the concentration of B and halve the concentration of C.
b) double the concentrations of both products and then quadruple the container volume.
c) double the container volume.
d) double the concentrations of both products.
e) add more A.
f) double the concentrations of both products and then double the container volume.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

thats how its supposed to be

i think its 100

i hope this !

d : a person who learns about the world by observing it. no that is not a smiley face

explanation: