Ca3(PO4)2 + 3 H2SO4 ⟶ 2 H3PO4 + 3 CaSO4

Joaquin needs to react [m] grams of calcium phosphate. He will need to measure out grams H2SO4 for this reaction.

The answer to your question is below

Explanation:

Balanced chemical reaction

               Ca₃(PO₄)₂  +  3H₂SO₄   ⇒   2H₃SO₄  +  3CaSO₄

To answer this question just calculate the molar mass of both reactants.

Molar mass of Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

                                         = 120 + 62 + 128

                                         = 310 g

Molar mass of 3H₂SO₄ = 3[(2 x 1) + (1 x 32) + (4 x 16)]

                                      = 3[2 + 32 + 64]

                                      = 3[98]

                                      = 294 g

Conclusion

310 g of Ca₃(PO₄)₂ will react with 294 g of 3H₂SO₄

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.