List the following aqueous solutions in order of decreasing boiling point. 0.120 mm glucose, 0.050 m LiBrm LiBr, 0.050 m Zn(NO3)2m Zn(NO3)2 . Rank items in order of decreasing boiling point.

0.050 m LiBrm LiBr < 0.120 mm glucose <0.050 m Zn(NO3)2m Zn(NO3)2

Explanation:

The above aqueous solutions show that LiBr low boiling point followed by glucose and Zinc.

using the equation of boiling point elevation

ΔTb = i×Kb×M

Making temperature constant at a value of 290K you can simple do a calculation to conform the boiling point.

looking the van hoff values for Znc = 3 , LiBr = 2 and glucose = 1

(glucose)ΔTb = i×Kb×M = 1×290k×0.120 = 34.8

(Zinc) = 3×290×0.050 = 43.5

(LiBr)  = 2×290×0.050 =29

∴ in conclusion LiBr has a the lowest decreasing boiling point

d is

a. hope i'm right

explanation: