The specific heat capacity of water is 4.18 J K⁻¹ g⁻¹. What is the enthalpy (heat) change when 10.00 g of water is heated from 285.0 to 300.0 K (Hint temperature change is the same in °C or Kelvin)?

627j

Explanation:

H=mcΔT

ΔH= 10*4.18*(300-285)

ΔH=10*4.18*15

ΔH=627j

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error