Some CH2Cl2 is placed in a sealed flask and heated to 517 K. When equilibrium is reached, the flask is found to contain CH2Cl2 (3.42×10-2 M), CH4 (3.69×10-2 M), and CCl4 (4.12×10-2 M). What is the value of the equilibrium constant for this reaction at 517 K?

The value of equilibrium constant for the given reaction at 517 K is 1.30

Explanation:

The chemical equation for the dissociation of follows:

The expression of for above equation follows:

We are given:

Putting values in above expression, we get:

Hence, the value of equilibrium constant for the given reaction at 517 K is 1.30

a) the particles of the chair are strongly held together.