Ammonia NH3, can be synthesized by the following reaction: 2NO + 5H2 → 2NH3 +2 H2O If you start with 90.0 grams of NO and an unlimited supply of H2, how much water is produced?

3 moles of water i.e. 54 gram of water is produced by starting the reaction with 99 grams of NO

Explanation:

The reaction to produce ammonia is shown below:

2NO + 5H2 → 2NH3 +2 H2O

From the reaction it is seen that NO is the limiting reagent in the reaction.

Atomic weight of NO=30.01 g/mol

the weight of NO in reaction is given 90 grams

Number of moles= 90÷30.01

                             = 2.99 or 3  moles of NO

It can be seen that 3 moles of NO is taking part in the reaction.

From the chemical equation it is seen that 2 moles of NO will yield 2 moles of water and 2 moles of ammonia.

From the stoichiometry:

2 moles of NO will yield 2 moles of O

3 moles of NO will yield x moles of O

x= 3 moles

The weight of water produced can be obtained by the formula

Number of moles= weight ÷atomic weight

     weight= 18×3

                 = 54 grams

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